太原市2023年高三年级模拟考试（二）物理参考答案及评分建议二、选择题:本题共8小题，每小题6分，共48分。在每小题给出的四个选项中，第14～18题只有一项符合题目要求，第19～21题有多项符合题目要求。全部选对的得6分，选对但不全的得3分，有选错的得0分。题号1415161718192021选项CDCDCCDCDAB三、非选择题：共62分。22.（8分）（1）A（2分）（4）（2分）（2分）（2分）sin��2cos�−�1cos��1sin�+�2sin�其si他n�正确答案均可得�分�1cos�+�2cos�23.（10分）（1）C（1分）D（1分）E（1分）（2）b（1分）b1（2分）或（2分）�1�1���1�2�2（3）（2分）（其他�1合−理�说1+法�均�可−得分）�2−24.（1�0V分≫）�+�2解：（1）对a束光sin60n3···········································································（1分）sina1sin，α=30°············································································（1分）2{#{QQABLYAQoggIAJIAABgCQQXACEGQkBAAACoGBFAEIAAByRNABAA=}#}对b束光sin606n··········································································（1分）sinb22sin，β=45°·········································································（1分）2由光路图，出射a光束平行PO，出射b光束与PO成30°角，a、b两光束成30°············································································（1分）c（2）由v得ncva·························································································(1分)nacvb·························································································（1分）nb3R3R（分）ta··············································································1vac2R3R（分）tb············································································1vbct3a························································································（1分）tb125．（14分）（1）粒子在磁场做匀速圆周运动，在电场中做斜抛运动。由受力分析，粒子带正电，粒子回到O点时与MN的夹角为··················（3分）（2）在磁场中，洛伦兹力提供向心力�v2qvBm·····················································································（1分）rmvrqB从边界MN射出的位置记为P点，OP的距离为L·····················································································（1分）�在=M2N�上sin方�的电场中运动时，粒子做匀变速曲线运动竖直方向，粒子做匀变速直线运动··························································································（1分）